Re: [math-fun] The Axiom of Choice for roots of z^2 + 1
23 Nov
2007
23 Nov
'07
3:59 p.m.
P.S. In a faintly related vein, if we define i^z := exp(pi*z*i/2), then iterating this function on the starting value of z = i approaches a limit L of approx. 0.6528812343931018 + i 0.3675743023883531 (or so says my C program).
and for further information see entries A077589 and A077590 in the OEIS! Best regards Neil
6573
Age (days ago)
6573
Last active (days ago)
0 comments
1 participants
participants (1)
-
N. J. A. Sloane