Re: [math-fun] Visualizing f(z), mark II
James, what does f(z) stand for here? Any function f: C -> C ? Any entire function f: C -> C ? Something else? Thanks, Dan James Cloos wrote: << My previous code to attempt to visualize f(z) failed to usefully illustrate the map's behaviour. Perhaps this attempt will succeed. . . .
________________________________________________________________________________________ It goes without saying that .
"DA" == Dan Asimov <dasimov@earthlink.net> writes:
DA> James, what does f(z) stand for here? Any function f: C -> C ? DA> Any entire function f: C -> C ? Something else? The goal is any function which takes f: C -> C. Technically, though, it is any function which maps {complex double} -> {complex double}. The current code would end up mapping cases where isnan(f(x)) == true to black. But only because I didn't consider that case. As black is also the mapping of f(z) == 0., that may be a problem. :) I presume it would be better to map NaN to white like inf is? -JimC -- James Cloos <cloos@jhcloos.com> OpenPGP: 1024D/ED7DAEA6
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Dan Asimov -
James Cloos