Re: [math-fun] AB = B.AA seems to imply commutativity?
14 Feb
2006
14 Feb
'06
8:04 a.m.
David Moulton writes: << ab = b(aa) = (aa)(bb) = (bb)[(aa)(aa)] = (bb)[a(aa)] = (bb)(aa) = a(bb) = ba.
Nice one! --Dan
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