[math-fun] Is this familiar? For any f,
j j ==== /===\ \ 2 j n | | n n 2 j > ( ) (- 1) | | (f(k) - -) (1 + -) = ( ). / j - n | | k k j ==== k = 1 n = 0 E.g., for f:=1-ap^(k-1) j j ==== /===\ \ 2 j n | | n n k-1 > ( ) (- 1) | | (1 + -) (1 - - - a p ) / j - n | | k k ==== k = 1 n = 1 (a; p) = 1 - ----------------------------------------------------- . j 2 j ( ) j --rwg
participants (1)
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R. William Gosper