[math-fun] Re: Simple(?) Fib problem
5 Jan
2005
5 Jan
'05
3:38 p.m.
This is an interesting problem. If m is a multiple of 8, then the Fibs do not have every residue mod m since no Fib is congruent to 4 mod 8. Otherwise, I need to think about it further. Dave "David Wilson" <davidwwilson@comcast.net> 01/05/2005 07:17 AM To: "Sequence Fans" <seqfan@ext.jussieu.fr>, "math-fun" <math-fun@mailman.xmission.com> cc: Subject: Simple(?) Fib problem For which m for do the Fibs have every residue mod m?
6 Jan
6 Jan
1:40 a.m.
> This is an interesting problem. If m is a multiple of 8, then the Fibs do > not have every residue mod m since no Fib is congruent to 4 mod 8. > Otherwise, I need to think about it further. >From the numbers so far I'd conjecture the numbers contain 1. all powers of three 2. the numbers 1,2,3,4,6,7,14 3. if x is in the sequence, then 5x is, too. ralf
7625
Age (days ago)
7626
Last active (days ago)
1 comments
2 participants
participants (2)
-
David C Terr -
Ralf Stephan