Re: [math-fun] Distance matrix for symmetric group S_n
Thane wrote: << I'm confused. Shouldn't there be 4 \choose 2 = 6 permutations at distance one? Daniel Asimov wrote: Let the (usual) distance on the symmetric group S_n be given by d(p,q) = the least # of transpositions that will change p into q. Just did some little calculations with the symmetric group S_4 and found the # of perms at distance = d from 1234 to be these: dist: 0 1 2 3 4 5 6 nmbr: 1 3 5 6 5 3 1
Maybe I didn't express the definition of distance clearly, and/or maybe I'm using confusing notation. But there are only 3 transpositions one can apply to 1234: (12),(23), or (34). The 3 perms. at distance = 1 from 1234 [Note: 1234 doesn't mean the cycle (1234); it's the identity perm., the result of applying the identity to the initial position of 4 things, which I'm calling 1234] are the following: 2134, 1324, or 1243. (By the same token, *any* element of S_4 should also have exactly 3 perms. at distance = 1 from it.) Hope this clarifies things. --Dan
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Daniel Asimov