[math-fun] Can someone identify this number?
If you have a number-identifying program, and the time, can someone please tell me if this number, to 20 places, seems to be expressible in closed form* ? 0.33650841691839529162 (I have no strong reason to believe it can be, or can't be.) Many thanks -- and I greatly appreciate all the advice I got for numerically solving two eqns., two unknowns. --Dan _______________________ * You know what I mean. _____________________________________________________________________ "It don't mean a thing if it ain't got that certain je ne sais quoi." --Peter Schickele
You had perhaps already tried, but the Plouffe's inverter http://pi.lacim.uqam.ca/eng/ can't identify your number. Christian. -----Message d'origine----- De : math-fun-bounces@mailman.xmission.com [mailto:math-fun-bounces@mailman.xmission.com] De la part de Dan Asimov Envoyé : samedi 27 septembre 2008 02:07 À : math-fun Objet : [math-fun] Can someone identify this number? If you have a number-identifying program, and the time, can someone please tell me if this number, to 20 places, seems to be expressible in closed form* ? 0.33650841691839529162 (I have no strong reason to believe it can be, or can't be.) Many thanks -- and I greatly appreciate all the advice I got for numerically solving two eqns., two unknowns. --Dan _______________________ * You know what I mean. _____________________________________________________________________ "It don't mean a thing if it ain't got that certain je ne sais quoi." --Peter Schickele _______________________________________________ math-fun mailing list math-fun@mailman.xmission.com http://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun
Hello, I just tested that number (0.33650841691839529162) well with 20 digits, not much came out. I have this approximation ; -5 Pi Csch[Sqrt[5] Pi] + 3 Sec[Sqrt[5] Pi] - Sin[Sqrt[5] Pi] ------------------------------------------------------------ 10 which is good to 11 digits. but 11 digits this is half of an answer. simon plouffe
participants (3)
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Christian Boyer -
Dan Asimov -
Simon Plouffe