[math-fun] prime products - the next one
4 Feb
2012
4 Feb
'12
4:17 p.m.
0.125486980905809 = prod[p prime] (1 - 3/p^2) is the probability that n, n+1, n+2 all are squarefree. This number does not seem to be in Plouffe invertor, google, etc.
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Warren Smith