Re: [math-fun] a simple problem ?
On the other hand, I think Mike S. read Simon's intention correctly and I did not. --Dan ________________________________________________________________________________________ It goes without saying that .
Me too, I was not sure if the problem had a solution if we are in the continuous situation, but maybe I am wrong, the log and exponential solutions seems to be the one. have a nice evening, Simon Le 05/06/2012 20:36, Dan Asimov a écrit :
On the other hand, I think Mike S. read Simon's intention correctly and I did not.
--Dan
________________________________________________________________________________________ It goes without saying that .
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The situation is that at every point, the *estimated time* of the car reaching its destination is constant (without loss of generality, 1 hour). If we are at x, and the destination is 0, then we have: dx/dt = -x 1/x dx = -1 dt ln(x) = constant - t ln(x) = ln(x0) - t x = x0 exp(-t) x0 is the initial position of the car, when t = 0. This is the only solution. Sincerely, Adam P. Goucher
participants (3)
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Adam P. Goucher -
Dan Asimov -
Simon Plouffe