Hello, This is my first time posting here on math-fun. Let's see. If I understood your procedure correctly, I found that the largest of the first 100 terms is 1 919 922 020 352 Kris On Sat, Aug 15, 2020 at 01:12:24AM +0200, Éric Angelini wrote:

Hello Math-fun, We start S with a(1) = 2 and always extend S with the product « nth digit x nth term of S ». (When the product is = 0, we don’t extend S with 0 but with the smallest integer not yet present in S.)

S = 2, 4, 16, 16, 96, 96, 576, 5184, 31104, 279 936,...

We see that 2 x 2 = 4 = a(2) 4 x 4 = 16 = a(3) 1 x 16 = 16 = a(4) 6 x 16 = 96 = a(5) 1 x 96 = 96 = a(6) 6 x 96 = 576 = a(7) 9 x 576 = 5184 = a(8) 6 x 5184 = 31104 = a(9) 9 x 31104 = 279 936 = a(10) 6 x 279 936 = 1 679 616 = a(11) 5 x 1679 616 = ... etc.

The first column of the above array is the succession of the digits of S; the second column is the succession of the terms of S.

Question: what is the biggest of the first 100 terms of S? Best, É.

à+ É. Catapulté de mon aPhone

_______________________________________________ math-fun mailing list math-fun@mailman.xmission.com https://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun