Re: [math-fun] Prodigals (of matrices)
Hi, Shel. I'm not clear on how A(t) and B(t) depend on t in what you wrote below. I have posted a response to math-fun that should appear any minute. --Dan ------------------------------------------------------------------------------ -------------------------------- << If A and B are thought of as matrix-valued functions of a parameter t where, e.g., A(1/n) ^ n = A(1), B(1/n) ^ n = B(1), which makes easy to see geometric sense for constant rate rotations, then the product integral P (A(t)B(t))^dt seems to be the continuously combined rotation (at least according to one way of defining it), and seems to be equal to P (B(t)A(t))^dt.
The basic thought is that t is time and rotations proceed as a function of time. If matrix A is a rotation of x degrees, we can arrange that the matrix valued function A(t) = matrix A when t=1 and Identity when t=0. ( I probably should have chosen a different letter than "A" for the function since I don't have multiple fonts...) When t=x/n, A(t) = A(x/n). When this is raised to the power n, it means the rotation of x/n degrees is repeated n times, hence is a rotation of x degrees. I could imagine A(t) for a variable rotation rate, but for the constant rotation rate the parameter t linearly scales the rotation angle. The two dimensional case of A(t) would be [ cos(xt) sin(xt) ] [ -sin(xt) cos(xt) ] Apropos your response to math-fun, what relationship does Log(A) have to the eigenvector of A, if any? The other way to look at this sort of rotation combination is as a linear combination of the axes of rotation, and the axes are the eigenvectors of the rotation matrices. When I fiddled around with this stuff last time it came up, I could only make it work using the Log hack when A and B were rotations with the same axis. One of these days I'll "get it" for the more general case Shel At 06:18 PM 11/8/2002 -0500, you wrote:
Hi, Shel.
I'm not clear on how A(t) and B(t) depend on t in what you wrote below.
I have posted a response to math-fun that should appear any minute.
--Dan --------------------------------------------------------------------------------------------------------------
<< If A and B are thought of as matrix-valued functions of a parameter t where, e.g., A(1/n) ^ n = A(1), B(1/n) ^ n = B(1), which makes easy to see geometric sense for constant rate rotations, then the product integral P (A(t)B(t))^dt seems to be the continuously combined rotation (at least according to one way of defining it), and seems to be equal to P (B(t)A(t))^dt.
[The entire message from which the below was quoted was supposed to be a private note rather than to the whole list, so I didn't check it quite as carefully as I would have. Just getting used to the new mailing list. hint: when you reply to sender, it goes to the "reply-to" address, not the "from" address]. At 04:24 PM 11/8/2002 -0800, I wrote:
The basic thought is that t is time and rotations proceed as a function of time.
This *is* what I really meant, though I see that I got the time parameterization wrong. What A(t) and B(t) really are are matrices that express the instantaneous rate (and direction) of rotation per unit time at time t. So when they are constants over time, the product integral of one of them over time is a matrix that expresses an increasing rotation with time, like the usual parameterized (by some factor times angle) rotation matrix. This is a pretty nice analogy to a linear function being the integral of a constant. --Shel
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Shel Kaphan