[math-fun] Puzzle that Fermat posed to Mersenne
According to what I've read, Fermat posed this problem to Mersenne in 1943. This puzzle is intended for people who haven't seen the solution already: Find a primitive Pythagorean triple a^2 + b^2 = c^2 such that both a+b and c are each square numbers. (Please e-mail your answers straight to me so they don't keep others from solving this.) --Dan ________________________________________________________________________________________ It goes without saying that .
Nice, it's a problem of finding integer points on an elliptic curve. On Wed, Feb 8, 2012 at 2:51 PM, Dan Asimov <dasimov@earthlink.net> wrote:
According to what I've read, Fermat posed this problem to Mersenne in 1943. This puzzle is intended for people who haven't seen the solution already:
Find a primitive Pythagorean triple a^2 + b^2 = c^2 such that both a+b and c are each square numbers.
(Please e-mail your answers straight to me so they don't keep others from solving this.)
--Dan
________________________________________________________________________________________ It goes without saying that .
_______________________________________________ math-fun mailing list math-fun@mailman.xmission.com http://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun
1943?? How about a=-119, b=120, c=13^2 ? On Wed, Feb 8, 2012 at 4:51 PM, Dan Asimov <dasimov@earthlink.net> wrote:
According to what I've read, Fermat posed this problem to Mersenne in 1943. This puzzle is intended for people who haven't seen the solution already:
Find a primitive Pythagorean triple a^2 + b^2 = c^2 such that both a+b and c are each square numbers.
(Please e-mail your answers straight to me so they don't keep others from solving this.)
--Dan
________________________________________________________________________________________ It goes without saying that .
_______________________________________________ math-fun mailing list math-fun@mailman.xmission.com http://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun
Oops. I hit the reply, not the reply all, but I see that went to the list as well as Dan. Sorry about that. On Wed, Feb 8, 2012 at 10:57 PM, James Buddenhagen <jbuddenh@gmail.com>wrote:
1943??
How about a=-119, b=120, c=13^2 ?
On Wed, Feb 8, 2012 at 4:51 PM, Dan Asimov <dasimov@earthlink.net> wrote:
According to what I've read, Fermat posed this problem to Mersenne in 1943. This puzzle is intended for people who haven't seen the solution already:
Find a primitive Pythagorean triple a^2 + b^2 = c^2 such that both a+b and c are each square numbers.
(Please e-mail your answers straight to me so they don't keep others from solving this.)
--Dan
________________________________________________________________________________________ It goes without saying that .
_______________________________________________ math-fun mailing list math-fun@mailman.xmission.com http://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun
participants (3)
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Dan Asimov -
James Buddenhagen -
Victor Miller