Re: [math-fun] Playing with c = (a*b) mod (a+b)
Thanks to Chuck, Jack and Maximilian : http://www.cetteadressecomportecinquantesignes.com/ModuloPlay.htm Best, É. -----Message d'origine----- De : Eric Angelini [mailto:Eric.Angelini@kntv.be] Envoyé : lundi 7 juillet 2008 19:03 À : math-fun; seqfan@ext.jussieu.fr Objet : Playing with c = (a*b) mod (a+b) Hello MathFun & SeqFans, Start S = 2, 9,... Next term is (2*9)mod(2+9) 18 mod 11 = 7 S = 2, 9, 7,... Next term is (9*7)mod(9+7) 63 mod 16 = 15 S = 2, 9, 7, 15,... Next term is (7*15)mod(7+15) 105 mod 22 = 17 S = 2, 9, 7, 15, 17,... Next term is (15*17)mod(15+17) 255 mod 32 = 31 S = 2, 9, 7, 15, 17, 31,... Next term is (17*31)mod(17+31) 527 mod 48 = 47 S = 2, 9, 7, 15, 17, 31, 47,... Does this end in a loop? If yes, is there another start which doesn't? Best, É.
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Eric Angelini