[math-fun] Identities for Pi (03)
1 Sep
2018
1 Sep
'18
4:09 a.m.
Pi/8=sum(((-1)^n*(sqrt(cosh(t)^2+1)-cosh(t))^(2*n+1)*cosh((2*n+1)*t))/(2*n+1),n=0..infinity) ; For allt Pi/8=sum(((-1)^n*(sinh(t)-sqrt(sinh(t)^2-1))^(2*n+1)*sinh((2*n+1)*t))/(2*n+1),n=0..infinity) ; t in ]1 ;infinity[ Pi/8=sum(((sqrt(sin(t)^2+1)-sin(t))^(2*n+1)*sin((2*n+1)*t))/(2*n+1),n=0..infinity); t in]-Pi 0[; ]0 ; Pi[
2638
Age (days ago)
2638
Last active (days ago)
0 comments
1 participants
participants (1)
-
françois mendzina essomba2