Is every nonnegative integer of the form a^2 + b^2 - [sqrt(a^2 + b^2)]^2 ?
Are a, b, c required to be integers? Sent from my iPhone
On May 18, 2016, at 5:12 AM, Gareth McCaughan <gareth.mccaughan@pobox.com> wrote:
On 18/05/2016 02:20, David Wilson wrote: Is every nonnegative integer of the form a^2 + b^2 - [sqrt(a^2 + b^2)]^2 ?
No, but every nonnegative nonpositive integer is.
Or have I missed something?
-- g
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Here " [x] " denotes " floor(x) " , I think. WFL On 5/18/16, Gareth McCaughan <gareth.mccaughan@pobox.com> wrote:
On 18/05/2016 02:20, David Wilson wrote:
Is every nonnegative integer of the form a^2 + b^2 - [sqrt(a^2 + b^2)]^2 ?
No, but every nonnegative nonpositive integer is.
Or have I missed something?
-- g
_______________________________________________ math-fun mailing list math-fun@mailman.xmission.com https://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun
On 18/05/2016 14:13, Fred Lunnon wrote:
Here " [x] " denotes " floor(x) " , I think. WFL
On 5/18/16, Gareth McCaughan <gareth.mccaughan@pobox.com> wrote:
On 18/05/2016 02:20, David Wilson wrote:
Is every nonnegative integer of the form a^2 + b^2 - [sqrt(a^2 + b^2)]^2 ?
Ohhhhhh. -- g
Hello funsters, I made a QD program (quick and dirty) program to check the hypothesis of mr Wilson. Well, not certain, I could get the numbers in N from 1 to 2400 approx. in about 30 min of cpu. It could be true. This is the only empirical thing I can say so far. Best wishes and cheers. Simon Plouffe
participants (5)
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Cordwell, William R -
David Wilson -
Fred Lunnon -
Gareth McCaughan -
Simon Plouffe