A result in the same vein was that the zeta function zeta(x+iy) = Sum_{1 <= n < oo} 1/n^(x+iy) (defined, e.g., as above for x+iy with x > 1 and by analytic continuation everywhere else, except for x+iy = 1, where it's infinite). is sufficiently crazy (if you go far enough away from the x-axis on the critical strip given by {x+iy | 0 < x < 1}) that zeta(x+iy approximates any preassigned analytic function f(x+iy) *somewhere* to any degree of accuracy: (https://en.wikipedia.org/wiki/Riemann_zeta_function#Universality). —Dan

An interesting but probably useless result.

https://marginalrevolution.com/marginalrevolution/2018/05/one-parameter-equa...

Brent

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