Hmm, what about umpteen zillion? --Dan Hans wrote: << . . . So, let's prepend the 'two zillion' (2*10^n) and force the presumably- optimal 23 ending. 2*10^n (two zillion) +2*10^63 (two vigintillion) +2*10^36 (two undecillion) +2*10^12 (two trillion) +2000 (two thousand) +200 (two hundred) +20 (twenty) +3 (three) . . .

...

Sometimes the brain has a mind of its own.