Re: [math-fun] Smallest term in Zeckendorf representation
WFL said on May 16: PS --- Fibonacci product table, as defined using base-F' above: __0___1___2___3___4____5____6____7____8____9 __1___3___5___8__11___13___16___18___21___24 __2___5___8__13__18___21___26___29___34___39 __3___8__13__21__29___34___42___47___55___63 __4__11__18__29__40___47___58___65___76___87 __5__13__21__34__47___55___68___76___89__102 __6__16__26__42__58___68___84___94__110__126 __7__18__29__47__65___76___94__105__123__141 __8__21__34__55__76___89__110__123__144__165 __9__24__39__63__87__102__126__141__165__189 WFL Me: I am reading these messages in reverse order. This looks like an interesting array that should be in the OEIS (converted to a sequence by being read by antidaigonals). Fred, is it correct? If so, could you please linearize it and send it in the OEIS along with a definition? (In return for my telling you about A101330!) Thanks! Best regards Neil
On 5/17/08, N. J. A. Sloane <njas@research.att.com> wrote:
WFL said on May 16: PS --- Fibonacci product table, as defined using base-F' above: ... Me: I am reading these messages in reverse order. This looks like an interesting array that should be in the OEIS (converted to a sequence by being read by antidaigonals). Fred, is it correct? If so, could you please linearize it and send it in the OEIS along with a definition? (In return for my telling you about A101330!)
The variant table is identical to Knuth's original, except for redefining x (*) 0 = 0 (*) x = x instead of x (*) 0 = 0 (*) x = 0. I suggest a footnote in A101330 mentioning that this also results in an associative operation --- but it's almost certainly the "wrong" variation, because it conflicts with known explicit formulae for x (*) y when x is constant. This variant results from specifying that the coefficient of F_0 in the representation of 0 (alone) shall be 1 instead of 0, i.e. 0 = ...0001 instead of ...0000. I've looked at similar plausibilities, and the only other associative variant I've found involves representing (alone) 1 = ...0011 instead of ...0100, which gives the same "circle" product as the original. Fred Lunnon
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N. J. A. Sloane