19 Nov
2017
19 Nov
'17
10:49 a.m.
u_(n+1)=sqrt(2+2*u_(n))/2; u_(0)=-1; a_(n)=2^(k*(2*n+1))*sum((k!/((i!)*(k-i)!))*(-1)^(i)*u_(n)^i,i,0,k); n--- infinity; a_(n)---Pi^(2*k);
2924
Age (days ago)
2924
Last active (days ago)
0 comments
1 participants
participants (1)
-
françois mendzina essomba2