Re: [math-fun] Two twisted cubes
We can generalise this to other regular polytopes. Regular simplexes are pretty triv: f(2) = arccos(1/2) = pi/3 f(3) = arccos(1/3) f(4) = arccos(1/4) ... Sincerely, Adam P. Goucher http://cp4space.wordpress.com ----- Original Message ----- From: Warren Smith Sent: 10/09/12 11:02 PM To: math-fun Subject: [math-fun] Two twisted cubes Consider two 0-centered N-dimensional hypercubes, rotated with respect to each other. Let f(N) = max(over all rotations) min(over all red-blue vertex pairs AB) angle(A0B). For example, f(1)=0, f(2)=45 degrees. This function f is an interesting geometrical quantity. How does this sequence continue? What are its asymptotics? Does f(N) --> 0 when N-->infinity? Or to some positive constant (what)? I know f(4)>=45 degrees. I can prove f(N) > C for some positive constant C (which I could compute) for all large-enough N. I have no upper bound of the form f(N) < C < 90 degrees, but surely one must be true. _______________________________________________ math-fun mailing list math-fun@mailman.xmission.com http://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun
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Adam P. Goucher