[math-fun] Re: five, six, and eight
I asked earlier about the Lyness sequence, given by the recurrence L(n+1) = (L(n)+1)/L(n-1). Regardless of the initial conditions, a sequence satisfying this recurrence will be periodic with period 5; this is easy to verify, but I wanted to know "why". Some illumination came from reading parts of the paper "Y-systems and generalized associahedra" by Sergey Fomin and Andrei Zelevinsky, available over the web at http://www.math.lsa.umich.edu/~fomin/Papers/ (to appear in Annals of Mathematics), which Michael Kleber and I looked at. First, we may switch over to thinking about composition of the two rational functions F and G where F(s,t) = (s,(s+1)/t) and G(s,t) = ((t+1)/s,t) . F and G are both involutions, but if we take all alternating compositions ...(F(G(F(...(s,t)...)))... we get a group of 10 operations. In particular, G-compose-F is of order 5. Second, noting that the expressions for F and G are subtraction-free, we may replace the maps F and G their "tropical analogues" f and g, replacing the constant 1 by the constant 0 and replacing the arithmetical operations +, *, and / by max, +, and -: f(s,t) = (s,max(s,0)-t) g(s,t) = (max(t,0)-s,t) Note that f and g are continuous piecewise linear operations on the plane. Each of f,g is of order 2, but their composition g-compose-f has order 5. Moreover, the orbit of (1,0) under the action of the composed map is (1,0), (0,1), (0,-1), (1,1), and (-1,0) which we can recognize as being related to the Laurent polynomials x, y, (y+1)/x, (x+y+1)/xy, (x+1)/y from the Lyness sequence when they are written as (1) / x^{-1} y^{0} (1) / x^{0} y^{-1} (1+y) / x^{1} y^{0} (1+x+y)/ x^{1} y^{1} (1+x) / x^{0} y^{1} To see what's going on with f and g geometrically, it's most helpful to think of (1,0) and (0,1) as making an angle of 120 degrees, and to divide the plane up into 60-degree sectors. However, the maps f and g do not permute these sectors (if they did, then their composition could not have order 5 without forcing f and/or g to be discontinuous). Instead, some sectors are mapped into sectors, some sectors are expanded into a union of two adjacent sectors, and some sectors are contracted into a part of a sector. A similar situation prevails for the 6-fold periodic recurrence and for the 8-fold periodic recurrence, and there is a Lie-theoretic story for what's going, involving the root-lattice. E.g., for the original 5-fold case, if you examine the list above you can check that if we throw out the first two denominators (the ones with negative exponents), the resulting vectors (1,0), (0,1), and (1,1) are the positive roots of the Lie algebra A_2 (relative to the basis of simple roots). This happens much more generally. By the way: Does anyone see a way to combine the 10-fold Lyness action with the 6-fold rotation action on the 6 sectors to get the alternating group A_5, or anything like it? Low-dimensional piecewise-linear maps might give faithful representations of interesting groups whose linear representations are all higher-dimensional. Jim Propp
On Mon, Dec 09, 2002 at 07:31:23PM -0600, James Propp wrote:
I asked earlier about the Lyness sequence, given by the recurrence L(n+1) = (L(n)+1)/L(n-1). Regardless of the initial conditions, a sequence satisfying this recurrence will be periodic with period 5; this is easy to verify, but I wanted to know "why". ...
Second, noting that the expressions for F and G are subtraction-free, we may replace the maps F and G their "tropical analogues" f and g, replacing the constant 1 by the constant 0 and replacing the arithmetical operations +, *, and / by max, +, and -: f(s,t) = (s,max(s,0)-t) g(s,t) = (max(t,0)-s,t)
This hint led me to a different explanation of why this relation is true. There is a canonical source of period 5 phenomena: Consider the triangulations of a pentagon. There a 5 triangulations, and if you connect two triangulations that share a triangle, you get a 5-cycle. (Any two adjacent triangulations in this cycle are related by switching one diagonal of a quadrilateral for the other.) This same 5-cycle appears in many guises, in particular as the pentagon relation in category theory, related to the two diffrent ways to reparenthesize a(b(cd)) to ((ab)c)d: a(b(cd)) = a((bc)d) = (a(bc))d = ((ab)c)d a(b(cd)) = (ab)(cd) = ((ab)c)d To relate this to the problem at hand, consider 5 points in the complex plane. Up to Moebius transformations, the positions are determined by two cross ratios. A triangulation determines a choice of cross-ratios (one per diagonal): For each diagonal, apply a Moebius transformation to put the two endpoints at 0 and infinity; if the two adjacent vertices go to -x and y, the cross-ratio is defined to be y/x. It is easy to compute how the cross-ratios change when you flip a diagonal. They change by (l,m) -> (1/m, l(m+1)) which is related (by inverting the first component) to the expressions that Jim gave. Again, since switching the diagonals 5 times gets you back where you started, this transformation must be periodic with period 5. The reason the comments about tropical expressions ran a bell for me is that if you take this limit of the expressions for cross-ratios, you get corresponding expressions for transformations of curves on surfaces, which is something I've been thinking about a lot recently. One significant fact in this context is that the expressions you get (for any of the recurrences that Jim suggested) are a sum of monomials, or, equivalently, the PL functions are convex: they are the max of a number of alternatives. I don't yet have any geometric interpretation of the other recurrences, of periods six or eight. I'm still working on it... Best, Dylan
participants (2)
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Dylan Thurston -
James Propp