James Buddenhagen <jbuddenh@gmail.com> wrote:

So this finite sequence has 65627501 terms? Or maybe 65627502? Jim

I suppose this sequence is best 0-indexed: the 0th term is 1, the 1st term is f(1)=3, the second term is f^2(1)=4. In that case, the last term is f^65627501(1) = 123456978. Calculated in Mma, by the way: f[x_] := x + Module[{y=Complement[Range[9],IntegerDigits[x]]}, If[Length[y]>0,Min[y],0]] I can handle one-liners even with a 7-month-old in my arms... --Michael

On 12/10/06, Michael Kleber <michael.kleber@gmail.com> wrote:

...

123456978, after 65627501 iterations.

What did we do before computers could do millions of pointless calculations for us?...

--Michael

On 12/10/06, Eric Angelini <Eric.Angelini@kntv.be> wrote:

...

Hello Math-Fun,

What is the last term of the sequence starting with "1" and obeying the rule:

"Add to n the smallest positive integer sharing no digit with n"

Sequence should begin like this :

1,3,4,5,6,7,8,9,10,12,15,17,19,21,24,25....

Best,

E.

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