OOPS -- sorry Re: [math-fun] Games of Ramsey and van der Waerden
Gareth, Ohhh, now *I* see what you mean by the metric inherited from R^2, which of course *does* depend on the embedding. I'm so used to thinking about Riemannian metrics, that this is wha I was referring to on simple closed curves (but without saying so). (Sorry about that. At least I had the wisdom not to post it to the group.) But all's well that ends well, right? Regards, Dan << Ohhh, I see. I entirely misunderstood. I thought you meant the metric induced by the obvious embedding of G in R^2. With the clarification you've now provided, I agree that that's a fine definition, not least because it's equivalent to the one I prefer :-).
On Monday 30 October 2006 17:36, Daniel Asimov wrote:
Gareth,
Ohhh, now *I* see what you mean by the metric inherited from R^2, which of course *does* depend on the embedding.
I'm so used to thinking about Riemannian metrics, that this is wha I was referring to on simple closed curves (but without saying so).
(Sorry about that. At least I had the wisdom not to post it to the group.)
But all's well that ends well, right?
Right. But did you mean to post *that* to the group? :-) -- g
participants (2)
-
Daniel Asimov -
Gareth McCaughan