RE: [math-fun] Multiplicative Magic Squares
I love the idea of multiplicative magic squares. Using n^2 unknown but distinct vectors in R^n that are indexed by (i,j) for 1 <= i,j <= n, it's the same as finding nonnegative integer coordinates for these vectors such that all vectors (i, j0) for 1 <= i <= n sum to the same as all vectors (i0,j) for 1 <= j <= n (for all choices of 1 <= i0,j0 <= n). (Or did someone already mention this?) I'm interested in how magic these can be. I find the old rule of having all rows & columns plus the 2 diagonals sum to the same sum as rather dorky: the diagonals are kind of random. 1) Better here would be all rows & columns and broken diagonals (i.e., diagonals on the torus) multiply to the same product. 2) Best of all would be for simply all affine lines on Z_n x Z_n multiply to the same product. (This is when you repeat the same step (K,L) on the torus and first come back to your starting point with exactly n steps. (There are 4x4 additive magic squares with this property; I'm not sure if there are for any other n.) Are 1) or 2) possible for a multiplicative magic square (MMS)? (And is there a better name for an MMS than multiplicative magic square?) --Dan
From dasimov@earthlink.net 1) Better here would be all rows & columns and broken diagonals (i.e., diagonals on the torus) multiply to the same product.
I do not know if it is possible, but our smallest 4x4 example with product 5040 has already (by construction with the 2 latin squares) 2 magic diagonals + 2 magic broken diagonals. 1 12 30 14 10 42 3 4 21 5 8 6 24 2 7 15 (broken 12*10*6*7 and 30*4*21*2) Another interesting example, magic product 14400: 1 6 40 60 20 120 2 3 24 4 15 10 30 5 12 8 Exchange columns 1 and 2, or columns 3 and 4, or idem for rows: the square remains magic!!! Because each diagonal of the four inside 2x2 squares have always the same magic product 120. Christian.
From dasimov@earthlink.net 1) Better here would be all rows & columns and broken diagonals (i.e., diagonals on the torus) multiply to the same product.
From Christian Boyer I do not know if it is possible, but (...) (...) Another interesting example, magic product 14400: 1 6 40 60 20 120 2 3 24 4 15 10 30 5 12 8 Exchange columns 1 and 2, or columns 3 and 4, or idem for rows: the square remains magic!!! Because each diagonal of the four inside 2x2 squares have always the same magic product 120.
YES, POSSIBLE! Slightly moving numbers in my above 4x4 example, here is a nice pandiagonal multiplicative square: 1 40 6 60 24 15 4 10 20 2 120 3 30 12 5 8 Dan, all is OK: "all rows & columns and broken diagonals (i.e., diagonals on the torus) multiply to the same product" = 14,400 here. Should be the smallest possible product allowing that property! Christian.
Additive magic squares with the pandiagonal property are more commonly known as "diabolic".
participants (3)
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Christian Boyer -
dasimov@earthlink.net -
David Wilson