Re: [math-fun] a^x-b^x=c, solve for x ?
21 Oct
2018
21 Oct
'18
8:26 a.m.
I usually suggest the techniques in gosper.org/newsrope.pdf , but everything I've tried for 50^x - 49^x = 2 converges abysmally. —rwg On 2018-10-19 12:41, Henry Baker wrote:
I can solve this equation with Newton's iterations, but I was curious if there might be an elegant closed form solution.
I tried fiddling with hyperbolic trig functions, but nothing seemed any simpler.
real a>b>0,c>0
E.g., a ~ 50, b ~ 49, c ~ 2 => x ~ 1.1438929
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Bill Gosper