For n >= 0, we have |{floor(n/k): k in Z+}| = floor(sqrt(4n+1)). Can we find a similar formula for a(n) = |{floor(n/(k^2)): k in Z+}|? For which n is a(n) > a(n-1)? - David W. Wilson "Truth is just truth -- You can't have opinions about the truth." - Peter Schickele, from P.D.Q. Bach's oratorio "The Seasonings"