Yes Dave, you're right, of course -- thanks ! Best, É. -----Message d'origine----- De : math-fun-bounces@mailman.xmission.com [mailto:math-fun-bounces@mailman.xmission.com] De la part de Dave Blackston Envoyé : jeudi 26 mars 2009 20:45 À : math-fun Objet : Re: [math-fun] Freeman Dyson integer problem How about 11111111111? ;-) Actually, for mabcdef...jkl to be m times abc...klm, a would have to be 1, so there's no real way for your cycle to work unless all the values are 1.