Correction: Re: [math-fun] The Axiom of Choice for roots of z^2 + 1
23 Nov
2007
23 Nov
'07
2:24 p.m.
I wrote: << P.S. In a faintly related vein, if we define i^z := exp(pi*z*i/2), then iterating this function on the starting value of z = i approaches a limit L of approx. [[[erroneous value was here]]]. Hmmm, Mathematica seems to give a rather different answer. . . . . . .
I just had a stupid bug in the program. Duh. Now it's fixed and the program finds that the limit is approx. L = 0.4382829363310479 + i 0.3605924719745690, and this is confirmed by other calculation systems. (It took 183 iterations of i^z on the starting value z = i before successive values agreed within taxicab distance |x-xlast| + |y-ylast| < 10^(-9)). --Dan
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Dan Asimov