Re: [math-fun] geometry puzzle
Variation: Dissect a disk into congruent pieces, so that a small region around the center is within one of the pieces. -- Rich
This is also included in the problem from UPIG that I previously mentioned. From my 1991 edition, problem C6 "Cutting up squares, circles and polygons", at the bottom of page 87: "Stein asks whether it is possible to partition the unit circle into congruent pieces so that the center is in the interior of one of the pieces?[sic] It need not be on the boundary of all the pieces, as Figure C8 [on page 89] shows. Is it true that the pieces must have a diameter of at least one? The first question is also of interest for the regular n-gon, n >= 5 ." Actually, it's easy to do for the regular hexagon, so the last sentence should probably read "n = 5 and n >= 7". For the equilateral triangle and square, there are such dissections into 4 and 3 congruent pieces, respectively. What's the fewest number of pieces in such a dissection of the regular hexagon? Is there any update on any of these in a later edition of the book? Michael Reid
Actually, it's easy to do for the regular hexagon, so the last sentence should probably read "n = 5 and n >= 7".
It can be done for any n = 6m, by the following procedure: Choose any six vertices, which themselves form a regular hexagon. Label them, in cyclic order, ABCDEF. Reflect the polygonal arc AB in the line BF to obtain a congruent polygonal arc OB, and repeat for all cyclic permutations. We now have six pieces with bilateral symmetry, which can each be subdivided into two congruent pieces. Sincerely, Adam P. Goucher
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Adam P. Goucher -
Michael Reid