12 Nov
2012
12 Nov
'12
9:50 a.m.
I was thinking more in terms of general proof for all cases ;) On 12 Nov 2012, at 12:47, Hans Havermann wrote:
David Makin:
My thought was has anyone considered: a^p + b^p + c^p = d^p or indeed: a1^p + a2^p + a3^p + ..... an^p = b^p
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