8 Aug
2019
8 Aug
'19
10:28 p.m.
Cool! Better still, I think I know how to prove this. That is, I think I can prove that on average a random cross-section of a unit cube has perimeter pi. More soon, Jim On Thu, Aug 8, 2019 at 10:21 AM Tomas Rokicki <rokicki@gmail.com> wrote:
And here are the final lines after an overnight run. Note that accumulating billions of doubles in this fashion loses precision; I should have done my summing more carefully. But at least five of the digits are probably good.
At 8589934592 pts 4.0000236480264 area 2.66669753208071 perim 6.2832343008038
At 17179869184 pts 4.00001316709677 area 2.66668286448053 perim 6.28322083261956
At 34359738368 pts 4.00000967484084 area 2.66667855572835 perim 6.28320124178968