No, Maple just returns the sum, not evaluated. but.. my own inverter here found about 20 answers, and in the bunch : the exact expression : 1/2-1/4*ln(1+2^(1/2))*2^(1/2) I could have bet that Maple could do it. There is probably a way to force Maple to do it, with convert(), ? not certain. Also, another expression for that number here : 1/2-1/4*arctanh(1/2*2^(1/2))*2^(1/2) Also found using the inverter (the one with billion entries). Best regards, Simon Plouffe Le mer. 1 juil. 2020 à 07:12, Bill Gosper <billgosper@gmail.com> a écrit :
ries: Sum[(-4)^n/Binomial[2*n, n], {n, 0, Infinity}] == 1/2 + Log[-1 + Sqrt[2]]/(2*Sqrt[2])
Can Maple do this?
Craziness: Plouffe's old Inverter turns it into a much easier arcsinh sum, that Mathematica can do. But Maple seemingly could't when Plouffe tabulated it. —rwg _______________________________________________ math-fun mailing list math-fun@mailman.xmission.com https://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun