28 Nov
2005
28 Nov
'05
3:29 p.m.
11011011*TROIS + k*ZERO = TRENTETROISMILLIONSTRENTETROISMILLETRENTETROIS
What could be the highest value of « k » to make this equation doubly true ?
k = 9052154594080843506502230384781217375224160 E I L M N O R S T Z 0 4 6 5 3 2 7 8 9 1 -- Don Reble djr@nk.ca -- This message has been scanned for viruses and dangerous content by MailScanner, and is believed to be clean.