27 Feb
2013
27 Feb
'13
4:40 p.m.
ARGH! Neil proved it telescopes. Then I remembered gosper.org/stanfordn2.pdf page "10" (=4) Never mind. --rwg On Wed, Feb 27, 2013 at 3:05 PM, Bill Gosper <billgosper@gmail.com> wrote:
Sum[2^k/(1 + z^2^k), {k, -Infinity, Infinity}] == 1/Log[z] Can somebody tell me where? --rwg And, as Neil empiricizes, Sum[2^k/(1 + z^2^k), {k, 0, Infinity}] == 1/(z-1)