9 May
2019
9 May
'19
5:39 a.m.
Of course, but that's a condition on a, not directly on A. It's like saying "exp(z) equals its conjugate when exp(z) is real" rather than "exp z equals its conjugate when Im(z) is an integer multiple of pi". On Wed, May 8, 2019 at 8:32 PM <bradklee@gmail.com> wrote:
a_{p1^m1 p2^m2 ... p^m} = a_{p1^m1} a_{p2^m2} ... a_{p^m}
?? —Brad
On May 8, 2019, at 8:31 PM, Mike Stay <metaweta@gmail.com> wrote: Are there results on when it does?
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