[math-fun] 1/Pi^2

Hi, Dear Bill, I didn't quite understand your reccurence.It may be obvious, but not for me. here is another one I propose for 1 / Pi ^ 2. It is simpler to obtain and the method is disconcertingly simple. a[n+1]=2^(-2*n-5)/(1-sqrt(1-2^(-2*n-4)/a[n])); a[0]=1/8 n----- infinity a[n] ------- 1/Pi^2 Best regards