Another math-fun member, using a brief Mathematica program, also found 88. It looks as though that's the correct answer. (Though, I haven't yet compared the two sets of output, the other of which is in terms of 1's, 2's, and 3's.) --Dan Tom Duff wrote: << On Tue, 6 Dec 2011, math-fun-request@mailman.xmission.com wrote:
Date: Tue, 6 Dec 2011 16:17:33 -0800 (GMT-08:00) From: Dan Asimov <dasimov@earthlink.net> To: math-fun <math-fun@mailman.xmission.com> Subject: Re: [math-fun] Counting problem Message-ID: <10736092.1323217054054.JavaMail.root@elwamui-norfolk.atl.sa.earthlink.net>
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Ha -- and in my spare moments today I counted 87 (by hand).
So, can we split the difference and agree on 86 ?
--Dan
Allan wrote:
<< As luck would have it, this afternoon I had a boring staff meeting in which I enumerated all of them ... I think. And the answer is 85 ... I think.
I found 88. Here they are. Where is my mistake? (Each string has 3 for a 30 degree angle, 6 for 60, 9 for 90. These are the lexicographically smallest representatives of their equivalence classes.)
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