26 Jun
2014
26 Jun
'14
3:05 p.m.
Sorry, Robert, but I still don't understand. What is the meaning of "(v . <i, j, k>)" ? Do you simply mean a vector (= pure (imaginary) quaternion; i.e., S(v)=0) ? At 01:50 PM 6/26/2014, Robert Smith wrote:
Most formally speaking, for a quaternion Q and a vector v in R^3, and for * meaning quaternion multiplication,
Q # v = Q * (v . <i, j, k>) * Q^{-1}
where i, j, and k are the pure unit quaternions. Originally I said conj(Q) instead of Q^{-1} which is only correct some of the time.
Robert
On Thu, Jun 26, 2014 at 11:23 AM, Henry Baker <hbaker1@pipeline.com> wrote:
I didn't understand your "#" operation. Could you please try again?