4 Nov
2014
4 Nov
'14
8:09 p.m.
On 11/4/2014 9:18 PM, David Wilson wrote:
a^2 - b^2 = c^2 - d^2 = e^2 - f^2
a^2 + b^2 = c^2 + f^2 = e^2 + d^2
Any solutions in nonzero integers?
Given two triples of integers with their squares in arithmetic progression, with both progressions having the same common difference (e.g., 1, 29, 41 and 23, 37, 47), you can construct a solution with distinct nonzero integers, such as a = 37, b = 29, c = 23, d = 1, e = 47, f = 41. -- Fred W. Helenius fheleni@emory.edu