21 May
2004
21 May
'04
2:47 p.m.
Apart from the trivial example, k=2 isn't possible. R. On Fri, 21 May 2004, Jud McCranie wrote:
At 01:03 PM 5/20/2004, you wrote: Is it possible to arrange the numbers
from 1 to n in a cycle, so that each is a divisor of the sum of the previous k members? There's a trivial example with n = 3 and k = 2, but I haven't found others.
If my program is correct, there are no others for k=2 for 23 < n < 61. I haven't found any with k=3, but my program isn't sufficiently general to rule them out.
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