23 Apr
2019
23 Apr
'19
10:16 p.m.
See: http://oeis.org/A006051 On Tue, Apr 23, 2019 at 11:10 PM Dan Asimov <dasimov@earthlink.net> wrote:
Just happened to notice that in the centered hexagonal numbers
H_n = 1 + 6 T_n = 3n^2 + 3n + 1
we have H_7 = 13^2. Also H_0 = 1^2.
So I tried to find all such cases of
H_n = K^2,
but am not sure of the best way to proceed. Suggestions?
—Dan
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