Hans, Warut and Marc already gave you a value, but I'd remark that a calculation like this is doable because you're calculating various 3-adic analytic functions, and so you can expand them (think Taylor Series) and get a good enough approximation. The important point is that 10 = 1 mod 9, so is 3-adically close to 1. Therefore you can take its 3-adic logarithm, and calculate 10 to any integer power fairly easily. So where did this calculation come from? Victor On Mon, Apr 26, 2010 at 10:27 PM, Hans Havermann <pxp@rogers.com> wrote:
A large number n = 689*10^((5889*10^((578*10^196-218)/81)-165)/81)-1 and I would like to know the value of n mod 81. Is this doable?
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