Jim, what is the Propp median if there are m zeros and m fives (and zero everything else)? Dan, if you're going to bring in averages at all then why not go all the way and use THE average? But maybe the CDC was using some sort of hybrid like the one you suggest. D At 09:14 PM 9/28/2005, you wrote:
The picture was supposed to show a rectangle of width 1 and height 2 whose bottom is centered at x=1, and to the right of it, a rectangle of width 1 and height 1 whose bottom is centered at x=2.
The base of the first rectangle goes from x=1/2 to x=3/2, and the base of the second rectangle goes from x=3/2 to x=5/2.
The total area under the histogram is (1)(2)+(1)(1) = 3.
The area to the left of the line x=5/4 is (5/4-1/2)(2) = 3/2, which is half of the total area. So x=5/4 is the "median".
Jim
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