8 Jun
2012
8 Jun
'12
9:54 a.m.
If carryless addition over GF2 is XOR, that implies the truth table: +|0 1 -+--- 0|0 1 1|1 0 Therfore, given multiplication would look like: *|0 1 -+--- 0|0 0 1|0 1 then multiplicate is AND, yes? What am I missing? -JimC -- James Cloos <cloos@jhcloos.com> OpenPGP: 1024D/ED7DAEA6