12 Mar
2014
12 Mar
'14
6:04 p.m.
On 3/12/14, Warren D Smith <warren.wds@gmail.com> wrote:
Of course 4F3(x) and indeed any pFq(x) with p<=q+1, is defined for all complex x except for a set of measure zero, via analytic continuation. And this particular 4F3 is of course an algebraic function which makes that obvious.
--and http://functions.wolfram.com/HypergeometricFunctions/HypergeometricPFQ/ gives explicit formulas such as integral representations. Pade and Borel summation should also work.