9 Jun
2011
9 Jun
'11
4:02 p.m.
="Marc LeBrun" <mlb@well.com> This is interesting, but I'm still having trouble with "THE first quadrant".
Risking belaboring the obvious in the pursuit of clarity:
= Kieran Smallbone For example
2+4i = (-i).((1+i)^2).(1+2i)
where the primes 1+i and 1+2i are "positive" because both they lie
in the top right quadrant.
But x=1-i has no "positive" Gaussian integer divisors at all. Are we then to take the sum of the divisors of x to be zero? Similarly, is the sum of the divisors of 2 then to be 1+(1+i)+2 = 4+i? (Heh. Then there are no even perfect naturals. Are there any at all?)