27 Apr
2010
27 Apr
'10
12:53 a.m.
="Hans Havermann" <pxp@rogers.com> A large number n = 689*10^((5889*10^((578*10^196-218)/81)-165)/81)-1 and I would like to know the value of n mod 81. Is this doable?
This isn't horseshoes, but isn't it one of the nine values of the form 9k+4? Which one depends on what (5889*10^((578*10^196-218)/81)-165)/81 is mod 9... This value is presumably (5889*10^((578*10^196-218)/81)-165 mod 729)/81, &c?