16 Aug
2012
16 Aug
'12
1:11 p.m.
Presumably the finite subset is required to have at least two points; otherwise the condition is vacuously satisfied. (Well, SOMEONE had to say it...) Jim On Thu, Aug 16, 2012 at 2:42 PM, Dan Asimov <dasimov@earthlink.net> wrote:
Just noticed this problem, with one solution given, in an obscure article:
<< Find a finite subset of the plane such that for any two of its points the perpendicular bisector of the segment connecting them passes through exactly two points of the set.
--Dan _______________________________________________ math-fun mailing list math-fun@mailman.xmission.com http://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun