6 Feb
2016
6 Feb
'16
11:12 a.m.
I don't really know what I'm talking about, but: for the unit square, corners first present on even steps of the algorithm to produce the Hilbert curve, and corners first present on odd steps. They're the complements of each other, right? On Sat, 6 Feb 2016 at 18:04 David Wilson <davidwwilson@comcast.net> wrote:
Is there a fractal set M a la the Mandelbrot set where both M and its complement are dense on the plane?
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