6 Jan
2013
6 Jan
'13
5:55 p.m.
On 1/6/2013 2:33 PM, Henry Baker wrote:
Note that my "pushing out" algorithm approximates the sphere_from the inside_, in the sense that the 8 vertices of the cube lie on the surface of the sphere, and each new "pushed out" face will also have all of its vertices on the surface of the sphere.
Is that true? What about the trapezoidal faces that are pushed out, not just the central square one? I don't think their vertices can all lie on a sphere. Brent Meeker